(2x=7)^5=1/32

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Solution for (2x=7)^5=1/32 equation: 


30.4;3.5

25*sin(x)

x^3-(6*x^2)+12*x <= 8

(3*(2*r-2))/5 = 3*r-(2/3)

(-x)^3+2*x^2+4*x <= 0

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